Field notebook 03-16-79 - 06-03-81


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Field notebook 03-16-79 - 06-03-81

Material Information

Title:
Field notebook 03-16-79 - 06-03-81
Creator:
Parker, Garald G. (Garald Gordon), 1905-2000
Publication Date:
Language:
English
Physical Location:
Box 13

Subjects

Subjects / Keywords:
Aquifers -- Biscayne Acquifer (Fla.) ( lcsh )
Hydrogeology -- Florida ( lcsh )
Hydrology -- Florida ( lcsh )
Genre:
Field notes ( local )
Field notebooks ( local )

Record Information

Source Institution:
University of South Florida
Holding Location:
University of South Florida
Rights Management:
The University of South Florida Libraries believes that the Item is in the Public Domain under the laws of the United States, but a determination was not made as to its copyright status under the copyright laws of other countries. The Item may not be in the Public Domain under the laws of other countries.
Resource Identifier:
032968560 ( ALEPH )
891343127 ( OCLC )
G16-00046 ( USFLDC DOI )
g16.46 ( USFLDC Handle )

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Book

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CURVE AND REDUCTION TABLES Published by Eugene D ietzgen Co. 1. Radiu s CURVE FORMULAS sin D/2 2 . D e gr ee o f Curve: 3 . T a ng ent 4 . Le ngth o f C urv e: 5 . L on g Chor d 6. Midd l e O r d inate: 7 . Externa l D= roof A l so, sin D /2= T=R tan Yz I. I L=lOO D A l so, T = +c. L . C.= 2R s in Yz I. M = R (I-cos Yz I) E =-R--R Al E T ta t / I cos Yz I SQ, = n 74 • EXPL ANATION AND USE OF TABLES G i ve n P . I. S t a. 83+40.7, I = 45 20 ' and D =630' find : T for 1 Curve+ StationaP.C.=P .I.-T. T D C . From Tabl es V and VI T + . 1 9 7 =368.32 = 3 + 68.32 . Sta. P. C . =83+ 40.7 (3 + 68.32) =79 + 72.38 . P . T . =P. C.+L . and L = 100 b =100 = 697.38 Ther efo r e , P . T. =(79+72.38) + (6 + 97.38) =86+69.76 . Oflaets-Tan gent offsets vart (approximately) direc tl r. wi t h D and with the square o f the dis t ance . F r o m Tabl e II Tangent Offset for 100 eet =5.669 feet . Di. •tance . ( 2 7 62 ) ' = 80 S t a . P. C . =27. 62 . Hence offset =5.66 X 100 =.432 ft. Also, squar e of any distan ce, d ivi d e d by t wice t he r a di us equals the distance from tangent t o c u rve . Thus (2 7 . 62)2i-(2 X881.95) =.432 ft. Deflections-Deflectio n D for 100 f t .. %'. D for 50 ft .. etc. For "X" ft_. D eflection Ang l e ( i n m i n u tes) =.3 X X XD. For Sta. SO of above curve D e flection Angle =.3 X27.62 X6. 5 =53. 86'. A l so Deflec ti o n A n g l e =dfl. for l ft. from Table III XX= 1.95 6 30' X 2 7 .62 = 53.86 '. F o r Sta. 1 8 1 D eflect ion Ang l e =53.86'+-2 -=4 8 . 86'. Externals-From T a bl e V for 1 curve, w i t h central angl e o f 45 20' , E =479.6. Ther e for e, f o r 6 30 ' curve, E = + Co rrecti o n fr o m Tabl e VI = 7.378+ .039 =7. 4 1 7 .

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!d:S-/Ob 10 '31.1.;..) . LJ,..J:.k. -I ")., \ -, q? -...., s:;,q General Equations and Useful Data l. I J.r t' Symbol Numerical on Equation Va lu e Area of circle ... . ' ............... 7r d2 4 Area of Sector of Circle (Length o f arc = 1 ) ..................... . 1 / 2 lr Area of Segment of Parabola (app.) (c = chord; m = mid. ord.) .... . 2 / 3 cm Area of Segment of Circle .... . ... 2 / 3 cm C ubic Feet in 1 Cubic Meter ..... 35.3145 Cub i c Inches in 1 Imperial Gallon. 277 . 274 Cub ic Inches in 1 U . S . Gallon .... 231 Feet in 1 Meter ................. 3 .2808 Feet in 1 Mi l e ................... 5280 Gallons (Imperial) in 1 -Cubic Foot. 6.2321 Gallons (U.S . ) in 1 Cubic Foot .... 7.48 Mi l es in 1 Kilometer ............ . 0.6213 Pounds (Av.) in 1 Kilogram ...... 2.2046 Ratio of Circumfere nc e to Diameter 7r 3.14159 Reciproca l of 7r ...•..........•.. 0.31831 Square Feet in 1 Acre ............ 43, 560 Volume of Sphere ................ 4/3 7rr3 Table !.-Minutes in Decimals of a Degree. 1' . 0167 11' . 1833 21' . 3500 31• . 5167 41' .6833 51' . 8500 2 .0333 12 . 2000 22 . 3667 32 . 5333 42 . 7000 52 . 8667 3 .0500 13 .2167 23 .3833 33 . 5500 43 . 7167 53 .8833 4 .0667 14 . 2333 24 . 4000 34 . 5667 44 .7333 54 . 9000 5 . 0833 15 . 2500 25 .4167 35 . 5833 45 . 7500 55 . 9167 6 . 1000 16 . 2667 26 . 4333 36 .6000 46 . 7667 56 .9333 7 . 1167 17 .2833 27 . 4500 37 .6 167 47 .7833 57 .950 0 8 . 1333 18 . 3000 28 .4667 38 .6 333 48 .80 00 58 .966 7 9 .1500 19 . 3 167 29 . 4833 39 . 6500 49 . 8167 59 .983 3 10 . 1667 20 .3333 30 . 5000 40 . 6667 50 .8333 60 1.0000 Table in Decimals of a Foot. l-1< !{, y, %. I !,{ I •r., I v. I o>i11 I Vs I . 0052 007 8 0104 . 0156 . 020 8 . 0260 . 0313 .0521 . 0625 0729 I 2 3 ab I .4f 67 I 5&xi I I I 9 1 0 I 11 . 0833 .1667 . 2500 . 7500 . 8333 .9167

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., I 3e>b / 15' f..8' r. ,..., . 1z.. 11 1ss::-1..rt l l ... ., l( ... j pfJ> J d'I.. t,/ 2, TRIGONOMETRIC FORMUL.. B B B A-A-A-C b c I b c b I Right Triangle Oblique Triangles of Right Triangles FAlA. ab ab c c or nge . sm =,,cos=,.tan =7i , cot =0,sec =/i,cosec = .. 0 Given a, b a,c A, a A, b A, c Given A, B, a A, a, b a, b, C a, b, c a, b, c A, b, c A,B,C,a Required g A , 8 , c tan A=.!!.= cot B, c =v1ci'+bi =a b A, B, b sin A c-a) B, b, c B = 90-A, b =a cot A, c = sm . B, a, c B = 90-A, a= b tan A, c =--bcos A. B, a, /J. B = 90-A, a = c sin A, b = c cos A. Solution of Oblique Triangles Requ1rtd b =a sin B, C = 180._(A+B), ,. a . sin C b, c, c smA smA B. C, c sinB=bsinA a ' smA A, .ll. c A+B= 180-C,tant(A-B) = (a-b) tan t (A+B) a sin C a+b c=---sin A A. B,C s = a+b+c, sin t A = y(s-b)(s-c), 2 . b c sin t iJ.=v(s-a)(s-cJ.C=l80-(A+B) ac Area s = area-Vs(s-a) .(s-b) (s-c) Area .. bcsmA area= . 2--. Area area= a' sin B sin C 2 sin A REDUCTION TO HORIZONTAL Horizontal d i stanc.e •slope distance multiplied b y the cosme of the vtrtical angle . Thus, for a slope distance of 403 . 6 ft . and a vertical angle o f 4 • 40'-the cos i ne ot 4 • 40 ', taken from a table of natural triaonometncal funct10ns , -. 9967 , and homontal distance • 403. 6 .9967 -402. 27 fl. H oriro ntal dist a n c e Hor i zontal distance also-Slope distance mlous slope d i s tance t imn (I-c.osine of vertical Usinc the same ficuru as in the preceding example Cos .4' 40 ' • . 9967 .1-. 9967 • .0033 . 403 .6x. 0033 • l . 33 ft. H o r;zontal dlSt. • 403 . 6 1 . 33 • 402.27 ft. When the nse is known. the horizontal d i stan c e may be found by the following approximate Nie: the slope d i stance less tht square of the rise d1v1ded by Urtice the slope d11 tance . Thut, for,J slope distance o( 372 . S ft . , and a nst " of 15 ft. lht hori.ionLal distanct = 372.5 • 372.5-. 30 = 372.2 ft.

PAGE 69

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